How Do U Not Worry About Boys? How Can You Not Like Them And Keep Them Outta Ur Life? <\3?

From Friends Forum:

How do u not worry about boys? How can you not like them and keep them outta Ur life? <\3? ID how to not like a boy. I wanna focus on other things but I just can't. All Boys break my heart and I can't take it anymore. I just don't know what to do<\3 help!

Answer: aw Hun its OK, every girl goes through a stage like this in her life I wouldn't concentrate on DISLIKING them because in a way that will make you think about boys even more because your so focused on avoiding feelings. trust me you'll find a guy who is wonderful to and who wouldn't dare break your heart, not every guys a douche. Try to throw yourself into activities, I like sports best because it gives you NO time to think personal thoughts and all those drills really help pump stress out of your body :)

A Train Starts With Certain Number Of Passengers. At First Station 1\3 Of The Passengers Get Down And 96 New P?

From Rail Forum:

a train starts with certain number of passengers. At first station 1\3 of the passengers get down and 96 new p? a train starts with certain number of passengers. At first station 1\3 of the passengers get down and 96 new passengers get into the train.At next station 1\2 of the passengers now is 240, what was the number of passengers in beginning?

Answer: Another homework question! Train starts with X passengers. At the first stop 2X/3 passengers remain on board and 96 more get on: Train now has (2X/3)+96 passengers So far, so good. But what do you mean by "At next station 1/2 of the passengers now is 240..."?

Where Does The Christian Bible Say That Satan Was A Fallen Angel And That 1'\3 Off The Angels Became Demons?

From Religion & Spirituality Forum:

Where does the christian bible say that Satan was a fallen angel and that 1'\3 off the angels became demons? Where does the christian bible say that Satan (Lucifer) is a fallen angel and that 1'\3 off the angels became demons?

Answer: It doesn't say that word for word but here are some of the passages that support this idea. Revelation 12:3 And another sign appeared in heaven: behold, a great, fiery red dragon having seven heads and ten horns, and seven diadems on his heads. 4 His tail drew a third of the stars of heaven and threw them to the earth. And the dragon stood before the woman who was ready to give birth, to devour her Child as soon as it was born. Revelation 12:7 And war broke out in heaven: Michael and his angels fought with the dragon; and the dragon and his angels fought, 8 but they did not prevail, nor was a place found for them in heaven any longer. 9 So the great dragon was cast out, that serpent of old, called the Devil and Satan, who deceives the whole world; he was cast to the earth, and his angels were cast out with him.

How Can I Find A List Of Songs Played On 92.3 Now Fm?

From Music & Music Players Forum:

How can I find a list of songs played on 92.3 Now fm? I like a song on 92.3 FM but I don't know the name of the song or who the artist is. Can someone help me out. Please?

Answer: Go to WNW.yes.com and enter in the station's call letters. That should give you access to a live stream of everything the station is playing and back logs of everything they have played all day, for days in the past, and their overall top tracks.

How To Find The Empirical Formula Of A Hydrocarbon By Percentage?

From Chemistry Forum:

How to find the empirical formula of a hydrocarbon by percentage? A hydrocarbon, X, contains 92.3 % Carbon by mass. Calculate the empirical formula. Mr= 78 What is the molecular formula? Please can you show the working? I'm not quite sure how converting it to grams etc helps. Thank you

Answer: A hydrocarbon, X, contains 92.3 % Carbon by mass. Calculate the empirical formula. Mw= 78 carbon is 92.3%, so divide by carbon's atomic weight. that's 7.69 hydrogen is 7.7% (i.e. 100-92.3). divide by hydrogen's atomic eight to give 7.7. Since the numbers are the same, that means the empirical formula is CH. But since you have the MW as 78, and CH is 13, the actual formula is 78/13, or 6 times the empirical formula. So: CH, which is benzene.

My Best Friend Has A Temperature Of 92.3. Is That Normal And Should I Be Concerned?

From Other - Health Forum:

My best friend has a temperature of 92.3. Is that normal and should I be concerned? We were planning to go to the mall today for an ultimate shopping spree, then she called and told me that she had a temperature of 92.3. She told me that much and not what the doctor said, so should I be concerned?We've been planning on this for months so I know shes not faking.

Answer: That temperature is quite low and yes you should be concerned. Drinking something cold before a test does not make a difference to the entire bodies temperature, it only makes a difference to the temperature of the stomach. Ask her what the doctor had said and if there was anything to worry about as she might be trying to conceal it from you so that you dint have to worry about her. As for the shopping spree, I know it would be a big let down for you so try not to take it to hard on the shoulders. Go round to her place and make another date in the near future once your BF is well Good luck and I hope your friend gets better soon

What Is The Partial Pressure Of Oxygen In The Oxygen And Helium Mixture?

From Chemistry Forum:

What is the partial pressure of oxygen in the oxygen and helium mixture? A mixture of oxygen and helium is 92.3% by mass oxygen. It is collected at atmospheric pressure (735 Torr). What is the partial pressure of oxygen in this mixture? a) 299 Torr b) 412 Torr c) 688 Torr d) 333 Torr e) 446 Torr (an explanation would be very helpful, especially what the purpose of the 92.3% would help indicate or just any help at all.)

Answer: First molecular masses: O2: 32, He: 4. A mixture of oxygen and helium is 92.3% by mass oxygen. Thus is 7.7% helium by mass. Now to find the mole percentage: O2: {92.3%/32} / {92.3%/32 + 7.7%/4} = 60% He: {7.7%/4} / {92.3%/32 + 7.7%/4} = 40% partial pressure of oxygen in this mixture: 60%735 Torr = 441 Torr.

What Is The Empirical Formula Of The Hydrocarbon?

From Chemistry Forum:

What is the empirical formula of the hydrocarbon? A certain hydrocarbon is 92.3 % carbon and 7.7 % hydrogen by mass. a)What is the empirical formula of the hydrocarbon? Be sure to write the carbon first. b) If the molar mass of the hydrocarbon is approximately 40 g/mol, what is its molecular formula? Be sure to write carbon first. hey can someone show me how to this problem?

Answer: Keep in mind that the subscripts in a chemical formula tell the number of moles of each element in 1 mole of the compound. Therefore, you need to convert the given information to moles and then set up the moles to give a ratio of small, whole numbers. We do that by dividing all of the number of moles by the smallest number of moles. 1. Assume a G sample. Then the percentages becomes grams. 2. Convert the masses of C and H to moles 3. Divide each number of moles by the smallest number of moles. This ratio of small whole numbers give the subscripts. 4. Multiply by 2 if necessary to make the ratio into whole numbers. 92.3 g C x (1 Mil C / 12.0 g C) = 7.69 Mil C 7.7 g H x (1 Mil H /1 g H) = 7.7 Mil H The ratio is 1:1. The empirical formula is CH. 5. Next find the empirical molar mass. 13 g/mol 6. Divide the actual molar mass by the empirical molar mass to get a whole number. 3 7. Multiply each subscript in the empirical formula by this whole number to get the molecular formula. C3H3

How Would I Go About Working This Question And Can You Explain It To Me?

From Homework Help Forum:

How would I go about working this question and can you explain it to me? How would I work this question out. A hydrocarbon, W, contains 92.3% carbon by mass. The relative molecular mass of W is 78.0. Calculate the empirical formula. Calculate the molecular formula.

Answer: since carbon content of the hydrocarbon is 92.3%,,, hydrogen content will be 100-92.3 = 7.7% divide the respective %s by their molecular masses that is C% by 12(you will get 7.6) and H% by 1(you will get 7.7) to get the respective number of moles you will now get the mole ratio(divide by smallest number of moles whether hydrogen or carbon if you dint get whole number ratios) here the ratio you will get will approx be 1:1.(since 7.6/7.7 is approx 1)..therefore empirical formula is equal to CH (if the ratio were 2:3 the EM formula would be C2H3) now find n n is equal to molar mass( which is given)/empirical formula mass here n = 78/12+1 =78/13=6 molecular formula= empirical formula x n therefore molecular formula is equal to C6H6(benzene) glad I could help I love chemistry

A Mixture Of Oxygen And Helium Contains 92.3% By Mass O. What Is The Partial Pressure Of Oxygen?

From Chemistry Forum:

A mixture of oxygen and helium contains 92.3% by mass O. What is the partial pressure of oxygen? A mixture of oxygen and helium contains 92.3% by mass O. What is the partial pressure of oxygen being administered if the atmospheric pressure is 0.980 atm?

Answer: I just made a short video ( about 4:15 PM Pacific Time) which solves this problem and I am in the process of uploading it (takes about 20-30 min). I'l put a link to it on this page: http://www.chemteam.info/GasLaw/KMT-Gas-Laws.html The answer is 0.588 atm Akito made a mistake by using 92,3 g of O. You have to use moles to get to the answer O2 moles is 2.884, He moles is 1.925, total moles = 4.809 mole fraction of the O is 0.600

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